题目：后台利用dom4j解析student.xml文件，并返回List<Student>集合

需要解析的XML：

<?xml version="1.0" encoding="UTF-8"?>
<classes>
 <class name="ST01">
 <student id="10001">user1</student>
 <student id="10002">user2</student>
 <student id="10003">user3</student>
 </class>
 <class name="ST02">
 <student id="10004">user4</student>
 <student id="10005">user5</student>
 <student id="10006">user6</student>
 </class>
 <class name="ST03">
 <student id="10007">user7</student>
 <student id="10008">user8</student>
 <student id="10009">user9</student>
 </class>
 <class name="ST04">
 <student id="10010">user10</student>
 <student id="10011">user12</student>
 <student id="10012">user13</student>
 </class>
 <class name="ST05">
 <student id="10013">user14</student>
 <student id="10014">user15</student>
 <student id="10015">user16</student>
 </class>
</classes>

java解析xml代码：

/**
 * @author hh
 */
public class XmlUtil {
 /**
 * 读取xml学生列表信息
 * @return
 */
 public List<Student> listStudent(){
 //创建SAXReader对象
 SAXReader reader=new SAXReader();
 Document document = null;
 try {
 //通过read方法读取一个文件 转换成Document对象
 document = reader.read(new File("/Users/mac/Documents/students.xml"));
 } catch (DocumentException e) {
 e.printStackTrace();
 }
 //获取根节点元素对象
 Element node = document.getRootElement();
 return elementMethod(node);
 }
 /**
 * 获取节点中的信息
 * @param node
 * @return
 */
 private List<Student> elementMethod(Element node){
 List<Student> list = new ArrayList<Student>();
 //获取所有class 节点
 List<Element> elementClass = node.elements("class");
 for (Element aClass : elementClass) {
 //获取所有student节点
 List<Element> elelmentStu=aClass.elements("student");
 for (Element element : elelmentStu) {
 //创建学生对象
 Student stu = new Student();
 //class节点里name的值
 stu.setSclazz(aClass.attribute("name").getValue());
 //student节点里ID的值
 stu.setSid(element.attribute("id").getValue());
 //student节点里的String值
 stu.setSname(element.getStringValue());
 list.add(stu);
 }
 }
 return list;
 }
}

实体类：

View Code

@Test 代码：

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运行结果：